Stress-Based Fatigue Analysis

Interactive Lecture

S-N Curves, Stress Concentration, and Fatigue Life Prediction

by Dr Arnaldo Delli Carri

Introduction to Fatigue Analysis

Fatigue is a failure mechanism that occurs in materials subjected to cyclic loading, even when the stresses are well below the material's ultimate tensile strength. By common estimates it drives roughly 80–90% of all in-service mechanical failures.

Key aspects that differentiate fatigue from static failure:

The tools below work through fatigue in four stages: characterising a stress cycle, reading life off an S-N curve, correcting for mean stress, and summing damage under variable-amplitude loading.

Fundamentals of Fatigue Loading

Stress Cycle Parameters

In fatigue analysis, we characterise cyclic loading using several key parameters:

\[\sigma_{max} = \text{Maximum stress in cycle}\]

\[\sigma_{min} = \text{Minimum stress in cycle}\]

\[\sigma_a = \frac{\sigma_{max} - \sigma_{min}}{2} = \text{Stress amplitude}\]

\[\sigma_m = \frac{\sigma_{max} + \sigma_{min}}{2} = \text{Mean stress}\]

\[R = \frac{\sigma_{min}}{\sigma_{max}} = \text{Stress ratio}\]

Loading Parameters

200
-100
0.5

Common Loading Types:

Stress-Time History

S-N Curves and Fatigue Life Prediction

The Wöhler Experiment

August Wöhler conducted the first systematic investigation of fatigue failure in the 1850s whilst studying railway axle failures. His experiments involved applying cyclic loads to test specimens until failure and plotting the results.

Basquin's Equation

The relationship between stress amplitude and fatigue life:

\[\sigma_a = \sigma'_f (2N_f)^b\]

Where:

On log-log scale: Appears as a straight line with slope = b

On semi-log scale: Appears as a curved (power law) line

Material Parameters

1000
-0.09

S-N Curve (Wöhler Diagram)

Log-log: Both axes logarithmic - shows power law as straight line
Semi-log: Only N-axis logarithmic - shows power law as curve

Understanding Scale Types:

  • Log-log scale: Makes power laws appear linear, useful for determining material constants (slope = b)
  • Semi-log scale: Better shows absolute stress values, commonly used in design handbooks
  • Toggle between scales to understand how the same data can be visualised differently

Effect of Mean Stress on Fatigue Life

In practical applications, many components experience cyclic loading with a non-zero mean stress. Tensile mean stress generally reduces fatigue life, whilst compressive mean stress tends to improve it.

Mean Stress Correction Models

Goodman: \(\frac{\sigma_a}{S_e} + \frac{\sigma_m}{S_{ut}} = 1\)

Gerber: \(\frac{\sigma_a}{S_e} + \left(\frac{\sigma_m}{S_{ut}}\right)^2 = 1\)

Soderberg: \(\frac{\sigma_a}{S_e} + \frac{\sigma_m}{S_y} = 1\)

Material Properties

800
600
300

Assessment Point:

200
150

Haigh Diagram

Cumulative Damage Theory

In real applications, components often experience variable amplitude loading. The Palmgren-Miner rule provides a way to assess cumulative damage.

Palmgren-Miner Linear Damage Rule

\[D = \sum_{i=1}^{k} \frac{n_i}{N_i}\]

Where:

Stress Block 1:

300
10000

Stress Block 2:

275
50000

Stress Block 3:

325
100000

Palmgren-Miner Damage Accumulation

Cycles to failure \(N_i\) for each block come from Basquin's equation for Steel 1045 (\(\sigma'_f = 1120\) MPa, \(b = -0.092\)), matching the Steel 1045 curve in the S-N section above.

Limitations of the Palmgren-Miner Rule:

Engineering Applications

Fatigue analysis applies wherever components experience cyclic loading:

Summary of Key Equations

Concept Equation Description
Stress Amplitude \(\sigma_a = \frac{\sigma_{max} - \sigma_{min}}{2}\) Half the stress range in cyclic loading
Mean Stress \(\sigma_m = \frac{\sigma_{max} + \sigma_{min}}{2}\) Average stress during cycle
Basquin's Equation \(\sigma_a = \sigma'_f (2N_f)^b\) S-N curve relationship for fatigue life
Goodman Criterion \(\frac{\sigma_a}{S_e} + \frac{\sigma_m}{S_{ut}} = \frac{1}{SF}\) Mean stress correction for fatigue design
Palmgren-Miner Rule \(D = \sum_{i=1}^{k} \frac{n_i}{N_i}\) Cumulative damage assessment (failure at D ≥ 1)

Practice Problems

Problem 1: Fatigue Life Prediction

A steel component (σ'f = 1000 MPa, b = -0.09) experiences fully reversed loading with a stress amplitude of 300 MPa. Calculate the expected fatigue life.

Show Solution

Problem 2: Mean Stress Correction

A component experiences σₐ = 200 MPa and σₘ = 150 MPa. If Se = 400 MPa and Sut = 800 MPa, calculate the safety factor using the Goodman criterion.

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Problem 3: Cumulative Damage

A component experiences three stress blocks: Block 1: 400 MPa for 1000 cycles (Nf = 10,000), Block 2: 300 MPa for 20,000 cycles (Nf = 100,000), Block 3: 200 MPa for 500,000 cycles (Nf = 10^6). Calculate the cumulative damage.

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Knowledge Check Quiz

Question 1: Stress amplitude for a cycle between 50 MPa and 250 MPa is:

Question 2: For fully reversed loading, the stress ratio R equals:

Question 3: Which material typically shows a distinct endurance limit?

Question 4: According to Palmgren-Miner, failure occurs when D equals:

Question 5: Which mean stress correction is most conservative?